-7x^2+4x+11=0

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Solution for -7x^2+4x+11=0 equation:



-7x^2+4x+11=0
a = -7; b = 4; c = +11;
Δ = b2-4ac
Δ = 42-4·(-7)·11
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-18}{2*-7}=\frac{-22}{-14} =1+4/7 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+18}{2*-7}=\frac{14}{-14} =-1 $

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